If $\begin{bmatrix} x+3 & z+4 & 2y-7 \\ -6 & a-1 & 0 \\ b-3 & -21 & 0 \end{bmatrix} = \begin{bmatrix} 0 & 6 & 3y-2 \\ -6 & -3 & 2c+2 \\ 2b+4 & -21 & 0 \end{bmatrix}$,then find the values of $a, b, c, x, y$ and $z$.
- A$a=-3, b=-7, c=-1, x=-4, y=-5, z=2$
- B$a=-6, b=-7, c=-1, x=-3, y=-8, z=2$
- C$a=-2, b=-9, c=-1, x=-3, y=-5, z=0$
- D$a=-2, b=-7, c=-1, x=-3, y=-5, z=2$
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